Iteratsiya usuli blok sxemasi




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Muhammad al-xorazmiy nomidagi toshkent axborot texnologiyalari u
Инновацион педагогик технологияларнинг мустақил таълимдаги аҳамияти, шпоры на госник сбор и подготовка, 632235-results-karakalpakstan-grade-6-1, Slayd Abdurahimova.N, 0202, -5307951, Abdunazarov Abdurashid 2F1 Optika, Moliya HUQUQIDAN USLUBIY MAJMUA, Xosmas integral, audit kurs ishi norbek, Rustamova Z, 12 tajriba ishi, 1 ПАТОК 2 СЕМЕСТР BOLALAR PSIXOLOGIYASI ЯКУНИЙ НАЗОРАТ САВОЛЛАРИ, vazifa 1 , Uskunaviy dasturlar
Iteratsiya usuli blok sxemasi


Tenglamarni oddiy iteratsiya usulida yechishning dasturi
#include
#include
using namespace std;
float f(float x)
{
return (exp(x)-2)/10.;
}


int main(){
float x, x0, e,a,b;
int n,i;
cout<<"birinchi yaqinlashish nuqtani kiriting";
cin>>x0;
cout<<"aniqligi";
cin>>e;
cout<<"iterasiyalar soni"; cin>>n;
x=x0;
for(i=1;i<=n;i++){
a=f(x);
if(fabs(x-a)<=0) break;
x=a;
}
cout<<"iterasiyalar soni="<
cout<<"noma'lum had="<
return 0;}

Quyidagi transsendent tenglamani oraliqni teng ikkiga bo’lish va iteratsiya usuli yordamida yechimini aniqlovchi dastur tuzing:

1. a) 2x­­­­­­­3-2x-1=0 b) 3x+cosx+1=0

2. a) x­­­­­­­3-x7=0 b) lnx+2 =0

3. a) 2x­­­­­­­3-2x2+3x+1=0 b) x+cosx-1=0

4. a) 2x­­­­­­­3-x-5=0 b)


5. a) x­­­­­­­3-3x2+2x-4=0 b) x2+4sinx=0

6. a) x­­­­­­­3+2x2+5x+2=0 b) lnx+x+1=0

7. a) 2x­­­­­­­3+2x-4=0 b) 2x-lgx=3

8. a) x­­­­­­­3-2x2+7x-1=0 b)

9. a) 2x­­­­­­­3+3x+4=0 b) x2=3sinx

10. a) x­­­­­­­3-3x2+6x+2=0 b) 3x-2lnx=4

11. a) x­­­­­­­3-2x+2=0 b) 4x-ex=0

12. a) x­­­­­­­3-3x2+2x-4=0 b) x(x+1)2=2

13. a) x­­­­­­­3+x-8=0 b) 3-2x=lnx

14. a) x­­­­­­­3-3x2+5x+1=0 b) 2x-cosx=0



15. a) x­­­­­­­3-x+2=0 b) sin(x/2)+1=x2



Laboratoriya mashg’uloti 3.1

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