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O'zbеkiston r
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| Sana | 28.04.2023 | | Hajmi | 131.23 Kb. | | #54574 |
Bog'liq O\'zbеkiston res Aniq integralni taqribiy hisoblash usullari To`g`ri to`rtburchak11
O'ZBЕKISTON RESPUBLIKASI AXBOROT TEXNOLOGIYALARI VA
KOMMUNIKATSIYALARINI RIVOJLANTIRISH VAZIRLIGI
MUHAMMAD AL-XORAZMIY NOMIDAGI
TOSHKЕNT AXBOROT TЕXNOLOGIYALARI UNIVЕRSITЕTI
KOMPYUTER INJINIRINGI FAKULTETI
Axborot texnologiyalari kafedrasi
ALGORITMLARNI LOYIHALASH
Mavzu:Chiziqli va tarmoqlanuvchi algoritmlar
BAJARDI:Abdurahmonov Otabek
TEKSHIRDI:Begimov Oybek
TOSHKENT 2022
Topshiriq №1
NxM o’lchamdagi ikki o’lchovli massiv (matritsa) hosil qilinsin va elementlari kiritilsin va matritsa ko’rinishida ekranga chiqarilsin, hosil bo’lgan matritsa elementlaridan variantdagi shartlar bo’yicha bir o’lchovli massiv hosil qilinib ekranga chiqarilsin.
2-variant
1-topshiriq:(nxm) o’lchamdagi ikki o’lchovli A massiv berilgan, matritsaning har bir ustinidagi musbat elementlari yig’indisidan tashkil topgan bir o’lchovli massiv hosil qiling
#include
#include
#include
using namespace std;
int main (){
srand(time(0));
int a[100][100],n,b[100];
cout<<"n = "; cin>>n;
for (int i=0; ifor (int j=0; ja[i][j] = rand()%5-1;
cout<}cout<}
cout<<"A[n][m] matritsaning har bir ustinidagi musbat elementlari yig'indisidan tashkil topgan P[n] bir o’lchovli massiv"<for (int i=0; ifor (int j=0; jif (a[i][j]>0) {
b[j]+=a[i][j];
} } }
for (int i=0; icout<}}
Topshiriq №2
#include
#include
float y(float x)
{
return (1-cos(x))/((x-sin(x))*(x-sin(x)));
}
float trapezoidal(float a, float b, float n)
{
float h = (b - a) / n;
float s =1;
for (int i = 0; i < n; i++)
s += y(a + i * h);
return h * s;
}
int main()
{
std::cout << "Natija: " << trapezoidal(3.14, 3.14*2, 100);
return 0;
}
#include
#include
float y(float x)
{
return (1-cos(x))/((x-sin(x))*(x-sin(x)));
}
float tort(float a, float b, float n)
{
float h = (b - a) / n;
float s = s = y(a) + y(b);
for (int i = 0; i < n; i++)
s +=2*y(a + i * h);
return(h / 2) * s;
}
int main()
{
std::cout << "Natija: " << tort(3.14, 3.14*2, 100);
return 0;
}
#include
#include
using namespace std;
float func(float x)
{
return (1-cos(x))/((x-sin(x))*(x-sin(x)));
}
float simpsons_(float ll, float ul, int n)
{
float h = (ul - ll) / n;
float x[101], fx[101];
for (int i = 0; i <= n; i++) {
x[i] = ll + i * h;
fx[i] = func(x[i]);
}
float res = 0;
for (int i = 0; i <= n; i++) {
if (i == 0 || i == n)
res += fx[i];
else if (i % 2 != 0)
res += 4 * fx[i];
else
res += 2 * fx[i];
}
res = res * (h / 3);
return res;
}
int main()
{
cout << simpsons_(3.14, 3.14*2, 100);
return 0;
}
Topshiriq №3
2-variant
#include
#include
#define EP 0.001
using namespace std;
double yechim(double x) {
return pow(2.71,x-1)-x*x*x*x*x+1;
}
void ikkiga_bolish(double a, double b) {
if (yechim(a) * yechim(b) >= 0) {
cout << "Siz a va b ni to'g'ri qabul qilmadingiz\n";
return;
}
double c = a;
while ((b - a) >= EP) {
c = (a + b) / 2;
if (yechim(c) == 0.0)
break;
else if (yechim(c) * yechim(a) < 0)
b = c;
else
a = c;
}
cout << "Tenglama ildizi : " << (c);
}
int main() {
double a, b;
cout << "a ni kiriting:"; cin >> a;
cout << "b ni kiriting:"; cin >> b;
ikkiga_bolish(a, b);
return 0;
}
Vatarlar usuli
#include
#include
using namespace std;
float f(float x) {
float f = pow(2.71,x-1)-x*x*x*x*x+1;
return f;
}
void secant(float x1, float x2, float E) {
float n = 0, xm, x0, c;
if (f(x1) * f(x2) < 0) {
do {
x0 = (x1 * f(x2) - x2 * f(x1)) / (f(x2) - f(x1));
c = f(x1) * f(x0);
x1 = x2;
x2 = x0;
n++;
if (c == 0)
break;
xm = (x1 * f(x2) - x2 * f(x1)) / (f(x2) - f(x1));
} while (fabs(xm - x0) >= E);
cout << "tenglama ildizi=" << (x0) << endl;
cout << "qadamlar soni = " << n << endl;
} else
cout << "javobi topilmadi";
}
int main() {
float x1 = 0, x2 = 1, E = 0.0001;
secant(x1, x2, E);
return 0;
}
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