2- amaliy mashg’ulot. Mashinali o’qitishda instrumental vositalardan foydalanish Matlab/Python dasturiy muhiti bilan ishlash

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2-амалиёт-(26-77)
1 курс кузги семестровка 2021 тегишли, Xazratqulov Shaxzod MTA , Sharipov Ruslan MTA , maqolam, Алишер Наваи, zamonaviy menejr, 123456, 37lFkFjlqjnzBLe61HBS0sH9a0FCpIBoVdby2gEd, 2-labaratoriya, kurs ishi nbb(2), Buxoro Norbutayeva Farangiz, Operatsion Tizimlar (Syllabus-2023-2024)-07, Fazluddin Iqroruddin. Nikoh va oila risolasi, Fibonachchi qo\'llanmasi

tril(A) - berilgan matritsaning diagonaildan yuqori qismini elementlarini 0 bilan almashtirishni amalga oshiradi. Misol. Berilgan matritsaning diagonaildan yuqori qismini elementlarini 0 bilan almashtirish: >> A=[-1 2 4 0 3; -2 1 0 3 4; -2 -1 0 -2 1; -2 3 -1 -1 1; 1 1 1 -1 -1] A = -1 2 4 0 3 -2 1 0 3 4 -2 -1 0 -2 1 -2 3 -1 -1 1 1 1 1 -1 -1 >> tril(A) ans = 0 0 0 0 1 0 0 0 -2 -1 0 0 0 -2 3 -1 -1 0 1 1 1 -1 -1 Endi shu buyruqni o’zimiz m-faylga yozib yangi yuqori degan buyruq hosil qilamiz (2.11-rasm). 2.11-rasm. >> B=yuqori(A) x = 5 B = -1 0 0 0 0 -2 1 0 0 0 -2 -1 0 0 0 -2 3 -1 -1 0 1 1 1 -1 -1 triu(A) - buyrug’i esa matritsaning diagonalidan pastki qismini nollarga aylantirishni amalga oshiradi. Misol. Berilgan matritsaning diagonaildan pastki qismini elementlarini 0 bilan almashtirish: >> A=[-1 2 4 0 3; -2 1 0 3 4; -2 -1 0 -2 1; -2 3 -1 -1 1; 1 1 1 -1 -1] A = -1 2 4 0 3 -2 1 0 3 4 -2 -1 0 -2 1 -2 3 -1 -1 1 1 1 1 -1 -1 >> triu(A) ans = -1 2 4 0 3 0 1 0 3 4 0 0 0 -2 1 0 0 0 -1 1 0 0 0 0 -1 Ushbu triu protsedurasini algoritmini o’zimiz tuzib m-faylga yozib chiqamiz va quyidagi natijalarga erishamiz (2.12-rasm). 2.12-rasm. >> B=pastki(A) x = 5 A = -1 2 4 0 3 0 1 0 3 4 0 0 0 -2 1 0 0 0 -1 1 0 0 0 0 -1 RESHAPE - matrisa o’lchamini o’zgartishni amalga oshirdi. >> A=[-1 0 2 0; 0 1 2 -1; -1 -2 -3 2] A = -1 0 2 0 0 1 2 -1 -1 -2 -3 2 >> reshape(A,2,6) % matritsa elementlarining soniga qarab ixtiyoriy o`lchamdagi matritsani hosil qiladi. ans = -1 -1 1 2 -3 -1 0 0 -2 2 0 2 Download 2.8 Mb.

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