Tashqi himoya qurilmalarini yoz sharoitiga moslab loyihalash

𝐴^𝑡𝑞 = 2,5 − 0,1 × ⁽𝑡
− 21⁾ = 2,5 − 0,1 × ⁽31,8 − 21⁾ = 1,42

𝑐_𝑖 ^𝑡

2. 
   
   
   Himoya konstruksiyasining yoz sharoitida issiqlik berish koeffitsientini aniqlaymiz:
   

𝛼_𝑇 = 1,16 × (5 + 10√𝑉) = 1,16 × (5 + 10√1) = 1,16 × 15 = 17,4

3. 
   Tashqi havo haroratini o’zgarish amplitudasining hisobiy qiymatini topamiz:
   

𝐴^𝑥 = 𝐴

× 0,5 + ⁽𝐼

− 𝐼

𝜌 0,7
⁾ × = 23,7 × 0,5 + ⁽579 − 177⁾ ×

𝑡_𝑟
𝑡_𝑟
𝑚𝑎𝑥

= 28,02

𝑜′𝑟𝑡
𝛼_𝑇
17,4

4. 
   Devor qatlamlarining tashqi sirtining issiqlik o’zlashtrish koeffitsientini hisoblaymiz:
   

𝑦₁
𝑅₁ × 𝑆² + 𝛼_𝑖

1
=
1 + 𝑅₁ × 𝛼_𝑖
0,009 × 22,86² + 8,7
⁼ 1 + 0,009 × 8,7
= 12,43

𝑦₂
𝑅 ₂ × 𝑆² + 𝛼_𝑖

2
= =
1 + 𝑅₂ × 𝛼_𝑖
0,82 × 0,8² + 8,7



1 + 0,82 × 8,7
= 1,13

𝑦₃

𝑅 ₃ × 𝑆² + 𝛼_𝑖

3
= =
1 + 𝑅₃ × 𝛼_𝑖
𝑅₄ × 𝑆² + 𝛼_𝑖
0,166 × 17,98² + 8,7



1 + 0,166 × 8,7
0,025 × 3,24² + 8,7

= 25,52

𝑦₄ =
4 ₌
1 + 𝑅₄ × 𝛼_𝑖
1 + 0,025 × 8,7
= 7,36

5. 
   Harorat o’zgarishlarini so’nish koeffitsienti quyidagicha aniqlanadi:
   

^∑ 𝐷
𝛾 = 0,9 × 𝑒 ^√2 ×
3,9
= 0,9 × 𝑒^√2
(𝛼_𝑖 + 𝑦₁⁾ × ⁽𝑆₁ + 𝑦₂⁾ × ⁽𝑆₂ + 𝑦₃⁾ × ⁽𝑆₃ + 𝑦₄⁾ × ⁽𝑆₄ + 𝛼_𝑇^{) (}𝑆₁ + 𝑦₁⁾ × ⁽𝑆₂ + 𝑦₂⁾ × ⁽𝑆₃ + 𝑦₃⁾ × ⁽𝑆₄ + 𝑦₄⁾ × 𝛼_𝑇

⁽8,7 + 12,43⁾ × ⁽22,86 + 1,13⁾ × ⁽0,8 + 25,52⁾ × ⁽17,98 + 7,36⁾ × ⁽3,24 + 17,4^{)
× (}22,86 + 12,43⁾ × ⁽0,8 + 1,13⁾ × ⁽17,98 + 25,52⁾ × ⁽3,24 + 7,36⁾ × 17,4
= 181,17

6. 
   Himoya konstruksiyasining ichki yuzasidagi harorat o’zgarishining amplitudasining hisobiy qiymatini quyidagicha aniqlaymiz:
   

𝐴_𝑐𝑖

𝑥

𝐴
= ^𝑡𝑟 =
𝛾
28,02



181,17

= 0,155