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“Fizika va texnologik ta’lim” jurnali | Журнал “Физико-технологического“Fizika va texnologik ta’lim” jurnali | Журнал “Физико-технологического
образование” | “Journal of Physics and Technology Education” 2021, № 4 (Online)
Journal of Physics and Technology Education | https//phys-tech.jspi.uz/
14
Let us consider the operation of the photocell in the field of large and small
powers in more detail. To simplify the calculations, we consider these cases as
separate modes.
1. The area of low power
In the low power region, the effect of losses in the series resistance R
s
is
negligible. The main losses are associated with the parallel resistance R
p
.
Accordingly, for this case, we can simplify the model by eliminating the
resistance R
s
. We calculate the efficiency of the photocell for this case
i
p
P
P
P
P P
where P
p
is the power loss in resistance R
p
. Thus, if we take the efficiency
threshold of 80%, then substituting it into the formula, we obtain the power
value P
min
at which such an efficiency is achieved
min
min
p
P
=0.8%.
P
+P
2. The area of great power
In the high power range, the power loss P
p
becomes insignificant compared to
the output, therefore, this type of loss can be ignored and R
p
can be excluded
from the circuit. Then, only the resistance Rs remains as the source of losses.
Similar calculations show that in this case for the load efficiency we have the
following expression
n
i
s
n
s
R
P
P
η=
=
=
.
P
P+P
R +R
The total load power
2
s
E
P=
η(1-η).
R
Fig. 1. The dependence of the efficiency on the power
P
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