P. S. Ixtiyoriy dasturlash tilidan foydalanish mumkin




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BekmirzaMadaminov7-8
Toshkenboyeva ZIlola Paradigma 7,8, dasturlash uslublari va paradigmalar, Muzaffarov Azizbek Dasturlash uslublari va paradigmalar mustaqil ish, Toshkenboyeva Zilola DTTL mustaqil ish 2, Muzaffarov Azizbek task 7,8, 8- amaliy ish Web xizmatlarning tarmoq modelini qurish, DHCP nima, Снимок экрана 2024—02—13 в 15.23.58

O’zbekiston Respublikasi Raqamli Texnologiyalar Vazirligi
Muhammad al-Xorazmiy nomidagi Toshkent Axborot Texnologiyalari Universiteti
Dasturiy Injiniring fakulteti talabasi Madaminov Bekmirzaning
Dasturlash uslublari va paradigmalar fanidan 7-8-shaxsiy topshiriqlari

Bajardi: Madaminov Bekmirza


PSP004-2 guruh
Qabul qildi: Atoyev Suhrob
G’afurovich

7-8-topshiriqlar


Task 7. Bolalarni dam olish maskaniga yuborish uchun kerak bo’ladigan avtobuslar soni.
Task 8. Shaxmatdagi otni yurishi orqali telefon raqamlarini hosil qilish.

P.S. Ixtiyoriy dasturlash tilidan foydalanish mumkin.

7. Dastur kodi (C++)
#include
#include
using namespace std;
int main(){
int k,b,m,n,x;
cout<<"Kattalar soni: "; cin>>k;
cout<<"Bolalar soni: "; cin>>b;
cout<<"O'rindiqlar soni: "; cin>>m;
n = m - 2;
x = b/n;
if(k<2 or b<0 or m<3)
{
cout<<"Impossible";
return 0;
}
if(b%n!=0){
x = x + 1;
}
if(k>=x*2 || k+b<=m){
cout<<"True"<cout<}
else{
cout<<"impossible";
}
return 0;
}

Dastur natijasi


8. Dastur kodi (Python)


import random
numbers = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
]
x_ = [1, 2, 3]
y_ = [1, 2, 3]
x__ = []
y__ = []
choices = [1, 0]
n = int(input("Enter a number: "))
def search_num(num):
n = num // 3 + 1 if num % 3 != 0 else num // 3
m = num % 3 if num % 3 != 0 else 3
return [[n - 1, m + 2], [n - 1, m - 2], [n + 1, m - 2], [n + 1, m + 2], [n - 2, m + 1], [n - 2, m - 1],
[n + 2, m + 1], [n + 2, m - 1]]
def check_num(nums, visited):
a = []
for i in nums:
if i[0] in x_ and i[1] in y_ and (i[0], i[1]) not in visited:
a.append([i[0], i[1]])
return random.choice(a)
for i in range(50):
visited_positions = set()
phone = str(n)
finish = 6
if n == 5:
print("xato")
if n == 0:
k = [4, 6]
phone += str(random.choice(k))
finish -= 1
for i in range(finish):
last = int(phone[-1])
k = search_num(last)
add_num = check_num(k, visited_positions)
visited_positions.add((add_num[0], add_num[1]))
phone += str(numbers[add_num[0] - 1][add_num[1] - 1])
print(phone)

Dastur natijasi



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P. S. Ixtiyoriy dasturlash tilidan foydalanish mumkin

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