• Jarayonlar navbati Oniy vaqti P1
  • Robin-Roundi algoritmi dasturi. include using namespace std; int main(){ int i,j,k=0,p=0,q,temp,s=0,idle=0,done=0;
  • Real vaqt tizimlarini yaratish texnologiyalari. Qisqacha nazariy ma’lumotlar




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    Real vaqt tizimlarini yaratish texnologiyalari. Qisqacha nazariy-hozir.org

    Laborotoriya qismi:
    Real vaqt tizimlarida Round-Robin algoritmi yordamida o’rtacha kechikish va minimum bajarilish vaqtini aniqlash.


    Jarayonlar navbati


    Oniy vaqti


    P1


    53


    P2


    17


    P3


    68


    P4


    24


    Vaqt bo`lagi=20 s


    P1


    P2


    P3


    P4


    P1


    P3


    P4


    P1


    P3


    P3


    0 20 37 57 77 97 117 121 134 154 162
    1. P1 >> 53-20=33 >> 33-20=13


    2. P2 >> 17


    3. P3>> 68-20=48 >> 48-20=28 >> 28-20=8


    4. P4>>24-20=4


    Kutish vaqti ( KV ) = Aylanish vaqti(AV) – Oniy vaqt ( OT )


    ->
    Kutish vaqti P1 = 134-53 = 81 ms
    Kutish vaqti P2 = 37-17 = 20 ms
    Kutish vaqti P3 = 162-68 = 94 ms
    Kutish vaqti P4 = 121-24 = 97 ms
    Umumiy kutish vaqti = 81+20+94+97 = 292 ms
    O’rtacha kutish vaqti = 292/4 = 73 milliseconds

    Tugash vaqti P1 = 134ms


    Tugash vaqti P2 = 37 ms
    Tugash vaqti P3 = 162 ms
    Tugash vaqti P4 = 121 ms
    Umumiy tugash vaqti UTV = 134+037+162+121= 454 ms

    Bundan,
    Oʻrtacha tugash vaqti = 454/4= 113.5 ms .



    Robin-Roundi algoritmi dasturi.

    #include
    using namespace std;
    int main(){
    int i,j,k=0,p=0,q,temp,s=0,idle=0,done=0;
    float sum=0;
    //taking input
    cout<<"Please enter the number of proces : ";
    cin>>p;
    int a[p][4];
    int b[p][5];
    cout<<"Please enter the Time Quantum : ";
    cin>>q;
    cout<<"\n\nProcess\tArrival\tBurst\n-------\t-------\t-----\n";
    for(i=0;i

    for(j=0;j<3;j++){


    cin>>a[i][j];
    }
    a[i][3]=a[i][2];//storing total time of each process to another cell
    }
    cout<<"\n\nTime-Line is as follows (Verticle View)....\n\n";
    i=a[0][1];
    while(done!=p){
    if(k==p)
    k=0;
    if(a[k][1]<=i){
    if(a[k][2]!=0){
    if(a[k][2]>=q){
    printf("%5d-----------\n |p-%-4d|\n",i,a[k][0]);
    a[k][2]-=q;
    i+=q;
    }
    else{
    printf("%5d-----------\n |p-%-4d|\n",i,a[k][0]);
    i+=a[k][2];
    a[k][2]=0;
    }
    if(a[k][2]==0){
    b[s][0]=a[k][0];
    b[s][1]=a[k][1];
    b[s][2]=i;
    b[s][3]=a[k][3];
    b[s][4]=((i-a[k][1])-a[k][3]);
    sum+=((i-a[k][1])-a[k][3]);
    s++;
    done++;
    }
    idle=0;
    }
    k++;
    }
    else{
    if(idle==0){
    idle=1;
    k=0;
    }
    else if(idle==1){
    printf("%5d-----------\n |Idle |\n",i);
    idle=2;
    i++;
    }
    else
    i++;
    }
    }
    printf("%5d-----------\n",i);
    cout<
    cout<<"Table of processes with completion record as they were completed\n\n";
    cout<<"\n\nProcess\tArrival\tFinish\tTotal\tWait\n------------------------------------\n";
    for(i=0;i
    cout<
    cout<<"\n\nAvg. Wait time = "<
    cout<<"\nProgrammed by : .\n\n";
    //system("pause");
    return 0;
    }
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