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#include #include using namespace std; double func(double x) { return x x x + x x x 1; } double derivative(double x) { return x x + x 1; } void newton(double x0, double epsilon) { double x1; int iteration = 0; do {
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| bet | 1/4 | | Sana | 18.05.2024 | | Hajmi | 6,35 Mb. | | #242306 |
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MUHAMMAD AL-XOZMIY NOMIDAGI TOSHKENT AXBOROT
TEXNOLOGIALAR UNIVERSITETI
ALGORITMLARNI LOYIHALASH
32 variant
Bajardi:SADULLAYEVA ASAL
Berilgan tenglamani vatarlar va nyuton usulida ishlovchi dastur.
#include
#include
using namespace std;
double func(double x) {
return x * x * x + 3 * x * x - x - 1; }
double derivative(double x) {
return 3 * x * x + 6 * x - 1; }
void newton(double x0, double epsilon) {
double x1;
int iteration = 0;
do {
x1 = x0 - func(x0) / derivative(x0);
iteration++;
if (fabs(x1 - x0) < epsilon)
break;
x0 = x1;
} while (true);
cout << "Nyuton usulida: " << x1 << endl;
cout << "Takrorlanishlar soni: " << iteration << endl; }
void secant(double a, double b, double epsilon) {
double x0 = a, x1 = b, x2;
int iteration = 0;
do {
x2 = x1 - func(x1) * (x0 - x1) / (func(x0) - func(x1));
iteration++;
if (fabs(x2 - x1) < epsilon)
break;
x0 = x1;
x1 = x2;
} while (true);
cout << "Vatarlar usulida: " << x2 << endl;
cout << "Takrorlanishlar soni: " << iteration << endl; }
int main() {
double x0 = 0.5;
double a = 0.5, b = 1.0;
double epsilon = 0.0001;
cout << "a)" << endl;
newton(x0, epsilon);
cout << "\nb)" << endl;
secant(a, b, epsilon);
return 0; }
Dastur natijasi:
Ustun asosining elementlari (B)
Dastlabki bosqichda biz aniqlagan asosiy elementlarni jadvalga o'tkazing:
B 1 = x 4 ;
B 2 = x 5 ;
B 3 = x 6 ;
Cb ustun elementlari
Ushbu ustunning har bir katakchasi mos keladigan qatordagi asosiy o'zgaruvchiga mos keladigan koeffitsientga teng.
Cb 1 = 0;
Cb 2 = 0;
Cb 3 = 0;
O'zgaruvchan o'zgaruvchilarning qiymatlari va P ustuni
Ushbu bosqichda hech qanday hisob-kitoblar talab qilinmaydi, shunchaki qiymatlarni dastlabki bosqichdan jadvalning tegishli kataklariga o'tkazing:
P 1 = 160;
P 2 = 142;
P 3 = 123;
x 1,1 = 15;
x 1,2 = 10;
x 1,3 = 5;
x 1,4 = 1;
x 1,5 = 0;
x 1,6 = 0;
x 2,1 = 10;
x 2,2 = 4;
x 2,3 = 12;
x 2,4 = 0;
x 2,5 = 1;
x 2,6 = 0;
x 3,1 = 4;
x 3,2 = 15;
x 3,3 = 10;
x 3,4 = 0;
x 3,5 = 0;
x 3,6 = 1;
Maqsad funksiyasi qiymati
Maqsad funktsiyasining qiymatini Cb ustunini elementlar bo'yicha P ustuniga ko'paytirib, mahsulotlarning natijalarini qo'shib hisoblaymiz.
Maks P = (Cb 1 * P 01 ) + (Cb 11 * P 2 + (Cb 21 * P 3 = (0 * 160) + (0 * 142) + (0 * 123) = 0;
Baholangan nazorat o'zgaruvchilari
Biz har bir boshqariladigan o'zgaruvchi uchun hisob-kitoblarni o'zgaruvchi ustunidagi qiymatni elementlar bo'yicha, Cb ustunidagi qiymatga ko'paytirish, mahsulotlarning natijalarini umumlashtirish va ularning yig'indisidan maqsad funktsiyasi koeffitsientini ayirish orqali hisoblaymiz. bu o'zgaruvchi.
Maks x 1 = ((Cb 1 * x 1,1 ) + (Cb 2 * x 2,1 ) + (Cb 3 * x 3,1 ) ) - k x 1 = ((0 * 15) + (0 * 10) + (0 * 4) ) - 1800 = -1800;
Maks x 2 = ((Cb 1 * x 1,2 ) + (Cb 2 * x 2,2 ) + (Cb 3 * x 3,2 ) ) - k x 2 = ((0 * 10) + (0 * 4) + (0 * 15) ) - 2000 = -2000;
Maks x 3 = ((Cb 1 * x 1,3 ) + (Cb 2 * x 2,3 ) + (Cb 3 * x 3,3 ) ) - k x 3 = ((0 * 5) + (0 * 12) + (0 * 10) ) - 1500 = -1500;
Maks x 4 = ((Cb 1 * x 1,4 ) + (Cb 2 * x 2,4 ) + (Cb 3 * x 3,4 ) ) - k x 4 = ((0 * 1) + (0 * 0) + (0 * 0) ) - 0 = 0;
Maks x 5 = ((Cb 1 * x 1,5 ) + (Cb 2 * x 2,5 ) + (Cb 3 * x 3,5 ) ) - k x 5 = ((0 * 0) + (0 * 1) + (0 * 0) ) - 0 = 0;
Maks x 6 = ((Cb 1 * x 1,6 ) + (Cb 2 * x 2,6 ) + (Cb 3 * x 3,6 ) ) - k x 6 = ((0 * 0) + (0 * 0) + (0 * 1) ) - 0 = 0;
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#include #include using namespace std; double func(double x) { return x x x + x x x 1; } double derivative(double x) { return x x + x 1; } void newton(double x0, double epsilon) { double x1; int iteration = 0; do {
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