• Birlashtirish (Union)
  • Komplement (Complement)
  • Hodisalar Algebrasi Xossalari Birlashtirish va Kesishning Assotsiativlik Xossasi
  • Birlashtirish va Kesishning Kommutativlik Xossasi
  • Imkonsiz Hodisa (Impossible Event)




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    Ilhom (Ehtimollik)

    Imkonsiz Hodisa (Impossible Event):

    • Hech qachon sodir bo'lmaydigan hodisa. Masalan, zar tashlashda 7 chiqishi: ∅\varnothing∅.

    2. Hodisalar Algebrasi
    Hodisalar algebrasi - bu hodisalar ustida amalga oshiriladigan amallar va ularning xossalarini o'rganadigan soha.
    Hodisalar Ustida Amallar

    1. Birlashtirish (Union):

      • A∪BA \cup BA∪B: A yoki B hodisasining sodir bo'lishi.

      • Misol: zar tashlashda 2 yoki 4 chiqishi: {2}∪{4}={2,4}\{2\} \cup \{4\} = \{2, 4\}{2}∪{4}={2,4}.

    2. Kesish (Intersection):

      • A∩BA \cap BA∩B: A va B hodisalarining ikkalasi ham sodir bo'lishi.

      • Misol: zar tashlashda juft son chiqishi va 2 dan kichik son chiqishi: {2,4,6}∩{1,2}={2}\{2, 4, 6\} \cap \{1, 2\} = \{2\}{2,4,6}∩{1,2}={2}.

    3. Komplement (Complement):

      • A′A'A′: A hodisasining sodir bo'lmasligi.

      • Misol: zar tashlashda 2 chiqmasligi: {1,3,4,5,6} \{1, 3, 4, 5, 6\}{1,3,4,5,6}.

    4. Farq (Difference):

      • A∖BA \setminus BA∖B: A hodisasidan B hodisasini olib tashlash.

      • Misol: zar tashlashda 1, 2, 3 chiqishi va 2, 3 chiqishini olib tashlash: {1,2,3}∖{2,3}={1}\{1, 2, 3\} \setminus \{2, 3\} = \{1\}{1,2,3}∖{2,3}={1}.

    Hodisalar Algebrasi Xossalari

    1. Birlashtirish va Kesishning Assotsiativlik Xossasi:

      • A∪(B∪C)=(A∪B)∪CA \cup (B \cup C) = (A \cup B) \cup CA∪(B∪C)=(A∪B)∪C

      • A∩(B∩C)=(A∩B)∩CA \cap (B \cap C) = (A \cap B) \cap CA∩(B∩C)=(A∩B)∩C

    2. Birlashtirish va Kesishning Kommutativlik Xossasi:

      • A∪B=B∪AA \cup B = B \cup AA∪B=B∪A

      • A∩B=B∩AA \cap B = B \cap AA∩B=B∩A

    3. Distribitivlik Xossasi:

      • A∪(B∩C)=(A∪B)∩(A∪C)A \cup (B \cap C) = (A \cup B) \cap (A \cup C)A∪(B∩C)=(A∪B)∩(A∪C)

      • A∩(B∪C)=(A∩B)∪(A∩C)A \cap (B \cup C) = (A \cap B) \cup (A \cap C)A∩(B∪C)=(A∩B)∪(A∩C)


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    Imkonsiz Hodisa (Impossible Event)

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