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Misol. Berilgan matritsani soat strelkasiga qarshi 900 ga burish uchun ishlatiladigan rot90(A) buyrug’i:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
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| bet | 3/8 | | Sana | 27.05.2024 | | Hajmi | 232,03 Kb. | | #255039 |
Bog'liq Matlab tizimida matritsalar ustida arifmetik amallar bajarishMisol. Berilgan matritsani soat strelkasiga qarshi 900 ga burish uchun ishlatiladigan rot90(A) buyrug’i:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
A =
-1 0 1
0 -1 0
1 -1 1
>> rot90(A)
ans =
1 0 1
0 -1 -1
-1 0 1
Endi shu amalning bajarilish tartibi ya’ni algoritmini keltiramiz:
>> for i=1:3; for j=1:3; C(i,j)=A(j,3-i+1); end; end; C
C =
1 0 1
0 -1 -1
-1 0 1
Misol. MATLABda matritsalarni chapdan o’ngga burishda fliplr buyrug’idan foydalanish:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
A =
-1 0 1
0 -1 0
1 -1 1
>> fliplr(A)
ans =
1 0 -1
0 -1 0
1 -1 1
Undan tashqari MATLABda maxsus ko’rinishdagi matritsalarni hosil qilish
imkoniyati bor. Ana shunday matritsalarni hosil qiluvchi buyruqlarni keltirib
o’tamiz:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
A =
-1 0 1
0 -1 0
1 -1 1
>> size(A)
ans = 3 3 % ya`ni matritsaning o`lchami (3x3) o`lchamga ega bo`ladi.
>> length(A)
ans = 3
>> ndims(A)
ans = % oxirgi hosil bo`lgan matritsaning elemntlari sonini chiqarish.
2
>> isempty(A)
ans = 0 % matritsaning elementlari mavjud bo`lgani uchun 0 qiymat qaytaradi.
Misol: Berilgan A va B matritsalarni bir biriga ko’paytirish:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
A =
-1 0 1
0 -1 0
1 -1 1
>> B=[1 1 0; 2 -1 0; 3 0 1]
B =
1 1 0
2 -1 0
3 0 1
>> A*B
ans =
2 -1 1
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Misol. Berilgan matritsani soat strelkasiga qarshi 900 ga burish uchun ishlatiladigan rot90(A) buyrug’i:
>> A=[-1 0 1; 0 -1 0; 1 -1 1]
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