3. To‘rt o‘zgaruvchili Karno kartalari
To‘rt o‘zgaruvchili Karno kartalarida ikki va uch o’zgaruvchili Karno kartalaridagi usullar qo‘llaniladi. Faqatgina to‘rt o‘zgaruvchili Karno kartalarida birinchi va to‘r tinchi ustunlar, birinchi va to‘rtinchi qatorlar bir-biriga qo‘shni hisoblanadi, chunki ular mos ravishda vertikal yoki gorizontal silindrlarga o‘ralsa, ushbu ustunlar yoki qatorlar bir-biriga qo‘shni bo‘lib qoladi. To‘rt o‘zgaruvchili Karno kartalarining to‘rtta burchagi ham bir-biriga qo‘shni hisoblanadi, chunki karta “sferaga” o‘ralsa, to‘rtta burchak bir-biriga qo‘shniga aylanadi.
Masalan; F(0,0,0,1)=F(0,0,1,1)=F(1,0,0,1)=F(1,0,1,1)=0
Karno kartasi bo‘yicha formulaning soddalashgan ko‘rinishi quyidagicha bo‘ladi: F(A,B,C)= BD
Quyida keltirilgan misollar uchun Karno kartalari tuzilsin, soddalashtirilsin, soddalashgan formulaga mos rele-kontakt sxemasi chizilsin:
5.1
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F(0,0,0)=F(0,1,1)=F(1,1,0)=F(1,0,0)=1
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5.2
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F(0,0,0)=F(0,1,0)=F(1,1,0)=F(1,0,0)=1
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5.3
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F(0,0,1)=F(0,1,1)=F(1,1,1)=F(1,0,1)=1
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5.4
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F(0,0,1)=F(0,1,0)=F(1,1,0)=F(1,0,1)=1
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5.5
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F(0,0,0)=F(0,1,0)=F(1,1,1)=F(1,0,1)=1
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5.6
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F(0,0,0)=F(0,0,1)=F(1,0,0)=F(1,0,1)=1
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5.7
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F(0,1,0)=F(0,1,1)=F(1,1,0)=F(1,1,1)=1
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5.8
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)=1
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5.9
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F(0,0,0)=F(0,0,1)=F(1,1,0)=F(1,1,1)=1
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5.10
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F(1,1,0)=F(1,1,1)=F(1,0,0)=F(1,0,1)=1
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5.11
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F(0,1,0)=F(0,1,1)=F(1,0,0)=F(1,0,1)=1
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5.12
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F(0,1,0)=F(1,1,1)=F(1,0,0)=F(1,0,1)=1
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5.13
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F(0,1,0)=F(0,1,1)=F(1,1,1)=F(1,0,1)=1
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5.14
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F(0,1,1)=F(1,1,0)=F(1,1,1)=F(1,0,1)=1
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5.15
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(1,1,0)= F(1,0,0)=F(1,0,1)=1
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5.16
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F(0,0,0)=F(0,0,1)=F(0,1,1)=F(1,1,0)= F(1,0,0)=F(1,0,1)=1
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5.17
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F(0,0,0)=F(0,0,1)=F(1,1,0)=F(1,1,1)= F(1,0,0)=F(1,0,1)=1
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5.18
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F(0,0,0)=F(0,1,0)=F(0,1,1)=F(1,1,0)= F(1,1,1)=F(1,0,0)=1
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5.19
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)= F(1,1,0)=F(1,0,0)=1
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5.20
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)= F(1,1,0)=F(1,1,1)=1
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5.21
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)= F(1,0,0)=F(1,0,1)=1
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5.22
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F(0,1,0)=F(0,1,1)=F(1,1,0)=F(1,1,1)= F(1,0,0)=F(1,0,1)=1
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5.23
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)= F(1,1,0)=1
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5.24
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F(0,0,0)=F(0,1,0)=F(0,1,1)=F(1,1,0)= F(1,1,1)=1
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5.25
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(1,1,0)= F(1,0,0)=1
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5.26
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F(0,0,0)=F(0,1,0)=F(0,1,1)=F(1,1,0)= F(1,0,0)=1
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5.27
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F(0,0,0)=F(0,0,1)=F(0,1,0)=F(0,1,1)= F(1,1,0)=1
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5.28
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F(0,1,0,1)=F(0,1,1,1)=F(1,1,0,1)=F(1,1,1,1)=0
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5.29
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F(0,0,0,0)=F(0,0,1,0)=F(1,0,0,0)=F(1,0,1,0)=0
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5.30
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F(0,0,0,1)=F(0,0,1,1)=F(1,0,0,1)=F(1,0,1,1)=0
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1 . 262 sonini ikkilik sanoq sistemasiga o`taqazamiz
262(10)=100000110(2)
Haqiqiylik jadvalini tuzamiz
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