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de3! ba5 10.ab4 cb6 11.dc5 bd4 12.ec5 fg5 13.fe3 ed4
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| bet | 118/139 | | Sana | 13.12.2023 | | Hajmi | 31,19 Mb. | | #117717 |
Bog'liq Shashka bo\'yicha o\'quv qo\'llanma 100000 9.de3! ba5 10.ab4 cb6 11.dc5 bd4 12.ec5 fg5 13.fe3 ed4.
Yutqazgan bo’lardi 13…gf6? 14.gh4 eg3 15.hf4 de5 16.fd6 gf4 17.eg5 hf4 18.ed2 fe3 19.df4 hg7 20.ba3 gh6 21.dc7 bd6 22.cb6 ac7 23.cd4 va hokazo.
14.cc7 ac3 15.bd4 bb4 16.ab2 ed6
17.ed2.
17.bc3! bd2 18.ec3 gh4 19.cb4 hf2 20.eg1 gf6 21.ba5 fg7
( 21…fe7? 22.gf2 fg5 23.fe3 ef6 24.dc5! db4 25.ac3 gh4 26.cd4 fg5 27.fe5X.) [N.Abatsiyev – M.Fazilov o’yinida quyidagicha bo’lgan:
21…hg7 22.hg3. Yutuqni qo’ldan chiqarmoqda: (22.gf2! fg5 23.fe3 gh4 24.hg3! hf2 25.eg1 gf6 26.gf2 fg5 27.fe3 fg7 28.ab6 dc5 29.ba7 cb4 30.dc5 bd6 31.ab8X)
22…fg5 23.de5 ge3 24.ec7 ed2 25.cd8 de1 26.gf2 ec3 27.gf4 cd4 28.fg3 da7 29.fe5 ag1 30.gf4 gh2 31.dh4 hg5! 32.hh8 fe7 va qoralar durangga erishishdi]. 22.ab6 fg5 23.de5 ge3 24.ec7 hg5 25.cb8 ed2 26.bg3! Ushbu yurishdan keyin qoralarning butun himoya tizimi xavf ostida qolmoqda, chunki endshpilda durangga erishish mumkinligi aniq emas 26…dc1 (26…de1 27.gh4X. )
(M.Fazilov – G.Vishnevskiy o’yinida quyidagicha bo’lgan:26…gf6 27.gh4 dc1 28.ba7 cd2 29.gf2! yutuqli yakun bilan). 27.ba7 gh4 28.gf2!
Faqat shunday. Tahlil shuni ko’rsatmoqdaki, qoralar endshpilni saqlab qola olishmaydi (muallif L.Tsipes).
17…ba3 18.bc3 gh4 19.fe5 hf2 20.eg1 df4 21.dc5 fe7 22.cb6 ed6 23.ba7 gf6 24.gf2.
24.ab8 yurishiga 24…fe3! zarbasi o’yinni saqlab qoladi.
24…hg7
Quyidagi yo’l ham mumkin edi: 24…dc5 25.cb4 (25.ab8 hg7 26.bg3 cd4 27.ce5 fd4 28.gh4 gf6! 29.hd8 hg5 30.dh4 ab2=) 25…ab2 26.bd6 bc1 27.dc3 hg5 28.dc7 gh4 29.cb8 fe3 30.fd4 ch6 durang bilan.
25.fe3! hg5! 26.ab8 fe5 27.ba7 gf6 Murakkab topiladigan yurish.
28.ab8 gh4! 29.ec3 ef4 30.bg3 hf2 31.cb6 fe1 32.ba7 eh4 33.de3 hf6! 34.ed4 fh4 35.ab8 he1.
Durangga rozi bo’lishdi. Juda chiroyli himoya!
G.Dorfman – M.Fazilov
“Bodyanskiy o’yini”debyuti
O’yinni xalqaro grossmeyster M.Fazilov tahlil qilgan.
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