Temir beton konstruktsiyon material bolip tabiladi




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Temir beton konstruktsiyon material bolip tabiladi. Temir beton -fayllar.org

1 ^ Q 0777

a= V 3 . 1 4=14sm b=b jj-n*a=116sm-6*14sm=32sm n- gewekler sani


, , , 22sm—14sm , ,

hn=hn= =4sm hc=h-a=22-3=19sm.


AoR^'r'f1-0-5'^)

b h0 h0

116 4 ✓ и гл г- 41 . _ _ _

AOr=— * — * ( 1 — 0 .5 * —)=0.68

OR

M

Ao-


Ь^/Iq

Ao= 140°o°okg *^ =0.89 A0 > A0R



0 ( ) 0 0R Element qabirg'anin qisiliwi menen esaplanadi.

Mcb-0.8*Rb* h[,<(b - b)*(ho - ha)

4 STYX

Mcb=0.8*144.5kg/sm2*4sm*(116sm-32sm)*(19sm—— )=621466kg*sm

M rh

Ascb- CJLTT

^*(h0
8
Ш


л _ 62 14 66kg* sm _лп-,г ,

Ascb= 4TTjr=10.75sm

3 4 О О kg / sm 2*( 1 9 sm ——)

Mk =M - Mcb=1400000kg*sm - 621466kg*sm=778534kg*sm

A= 778 5 3 4 kg * sm =039

3 2sm*(19sm)2* 144. 5 kg/sm2

Tablitsadan v ma'nisin aniqlaymiz v=0.735

Mk

Ask-


V*Hq*R
s


л _ 778 5 34kg*sm r л 2

A$k— ; r=16.4sm

Sk

As—16.4sm2+10.75sm2—27.15sm2



Tablitsadan 5 028 almatura alamiz 'ZA S=30.79sm2

9
Tema: Orayliq qisiliwshi elementler esabi kolonnalar.




Berilgeni:

Kese-kesimi 30smx30sm uzinlig'i l0=4.5m, beton klassi B25 beton qarsilig'i Rb=145kg/sm2, beton boyinsha isenimli koeffitsent фь=0.85, almatura klassi A-lll soziliwg'a bolg'an qarsilig'i Rs=3400kg/sm2, turaqli ju'k Ng=1300kN, waqtinshaliq ju'k Nkp=200kN bolg'anda kese-kesimi ha'm almatura kesim maydanin tan'lan'. 0 3 2

Sheshimi:

N=Ng+Nkp=1300kN+200kN=1500kN

As= Ф=1 dep alip

Rs



1S00° —123.25*900

As=—1 =11.49sm2 2 03 2 £ A s=16.08sm2



s 3400 ^ s

lo 450 „ „ Nb 1300 л

-=—=14 — = =0.8



b 30 N 1500

Tablitsadan фь ha'm фг ma'nislerin alamiz фь=0.836 фг=0.84


RS*AS

a=-
Rb*RA

3400*16.08 _

a= =0.5


123.25*900

ф=фь+2*(фг-фь)*а

ф=0.836+2*(0.84-0.836)*0.5=0.839 ф < фг

i~Rb*A As=-

s

150000_123 25*90Q

As^JL839 =19.96sm2



s

10


Tablitsadan 403 2 almatura alamiz Z As=32.17sm2


  1. 839*(123.25*900+3400*32.17)=1848.3kN > 1500kN




A ^9 17

ц=^ * 100%=£2i7* 100 %=2.95 %

^ 900

11
Qabirg'ali plitani esaplaw.




Berilgeni:
Tema:

Plita eni b=120sm, biyiklig'Ii h=30sm, beton markasi M300 beton qarsilig'i Rs=160kg/sm2, almatura klassi A-lll soziliwg'a bolg'an qarsilig'i Rs=3400kg/sm2, Фь=0.85, qorg'awshi qatlam a=3sm, beton awirlig'i 2300kg/m3, shlak beton qalin'lig'i h2=4sm, to'selgen asfalt h3=3sm, paydali ju'k Pf=850kg/m2.

Almatura kesim maydani tanlansin.

Sheshimi:

  1. Konstruktsiyanin' o'z awirlig'i boyinsha h1=6sm beton awirlig'i 2300kg/m3


#"=1*1*hi*Yoi



<gf=1*1*0.06*2300=138kg/m2
  1. Plita u'stine to'seletug'in shlak beton awirlig'i 1500kg/m3 , h3=4sm




5f"-i*i*h2*Yo2

=1*1*0.04*1500=60kg/m2


  1. To'selgen asfalt betonnan awirlig'i 1800kg/m3, h3=3sm


#3=1*1*h3*Yo3

=1*1*0.03*1800=54kg/m2

Konstruktsiyag'a ta'sir etiwshi paydali ju'k P//=850kg/m2 ja'mi q konstriktsiyanin' esapli ju'k.

q=.0?*n1+flr£*n2+03*n3+Pj/*n4

q=138kg/m2*1.1+60kg/m2*1.1+54kg/m2*1.1+850kg/m2*1.2=1288.4kg/m2

Plitanin' pralot aralig'i u'ken pralottin' kishkenege qatnasin esaplasaq 2 ge jaqin bolg'anliqtan konstruktsiyani balka spatinda esaplaymiz.

16


1 2 8 8.4-^j *( О . 8 9m)2* 1 m
h0=6sm-1.2sm=4.8sm

=63.78kg*m

16

12
А - 6378kg*sm Q2Q




0 1 0 0sm*(4. 8 sm)2* 13 6kg/sm2 .

Tablitsadan v nin' ma'nisin aniqlaymiz v=0.990

As= 6378kg*sm -=0.39sm2

s

Tablitsadan aling'an rulon setka 3/3 - 15 £A s=0.47sm2.

Qabirg'anin' boylama almaturalarin esaplaymiz. Qabirg'adag'i ju'kke qosimsha qabirg'alar arasindag'i quyilg'an shoplari awirlig'I menen o'z awirlig'i.

® n -F + в!

6- betonnin' ko'lemli awirlig'i;

F-plita maydani;

9n=50kg/m2.


2300 , __ ___

—— + 5 0=369kg/m



6*1.z

qn=(e! + в! + в! + P?)*bi b1=1.2

qn=(369kg/m2+60kg/m2+54kg/m2+850kg/m2)*1.2=1599.6kg/pog m Uzaq mu'detli

qn=(^2 + 92 + 9a + ^iH)*b1=(369+60+54+700)*1.2=1419.6kg/pog m Qisqa mu'detli

PH=Pnn*b1=150*1.2=180kg/pog m

Qabitg'ag'a plitanin' qabirg'alarinin' artiqmaqmashliq ju'lerin ta'sir etewi itimali menen esapli nagruskadan esaplaymiz.

q=(e 2 *n2 + в з *П3+ в 4 *n4+ Pi* ni)*bi

q=(369*1.1+60*1.1+54*1.1+850*1.2)*1.2=1861.56kg/pog m



q*l2

M=-


8

. . 1599.6*5.82

M= =6726kg*m

p

M = =7827.86kg*m


13

Nitral ko'sher polkada jaylasqan dep esaplaymiz.

hj > 0.2*h0 h0=30sm-3sm=27sm
7R77R6

A0=— =0.077 tablitsadan v=0.960



0

782786 _ _ ,

As= =8.9sm

s

Tan'lap alamiz 2 018

2 016 s=9.11sm2

14
Tema: Qisiliwshi elementler esabi, fundament.




Berilisi:

Kese-kesim o'lshemi 30sm x 30sm kolonna asti orayliq qisilg'an fundamentin' bekkemligin esaplaw. Ta'sir etiwshi esapli nagruska NP=1500kN. Fundament beton markasi B25 betonnin' soziliwg'a bolg'an qarsilig'i Rbt=1.05MPa, almatura klassi A-ll soziliwg'a bolg'an qarsilig'i Rs=2700kg/sm2, fundament jaylasiw teren'ligi H=1.5m, fundament asti tiykardin grunt qarsilig'i Rrp=0.32mPa. Almatura kesim maydanin tan'lan'.



Sheshimi:

Biz aldin ala narmativ nagruskani tawip alamiz. Ol to'mendegi formula menen aniqlanadi.

н

NH=T flm=1.2



vm

H

NH= =1250kN

1.2

Fundament asti sirtinin maydani.


NH

Аф—■


^rp ^rp*#

vrp=2t*m2 fundament asti grunt penen fundament ko'lemli salmag'i.

A0=———=4.3m2

Ф 3 2 - 2 * 1 . 5

Biz fundament astin kvadrat formada dep oylap onin' ta'replerin tawip alamiz. =V43=2.07m biz a x b 210sm x 210sm etip tan'lap alamiz.

^ 1500kN

бгр= =340kN/m2

гп

Isshi biyiklikti anqilaymiz;



hk*bk . 1# I Np
ho——-— + -

rp


15

. О.Зш+О.Згп 1 I 1500kN _ . _

ho= + - * I ш =0.16m

4 2 Л1 1 0 5 0^2 + 340 fcN/m2

Konstruktip talaplarg'a ko're fundament biyiligi h=1.5*30+25=70sm

Kallonanin' boylama almaturalarin ankerlew talaplarina ko're eger ds=15mm qoyilatug'in bosa to'mendegi talapqa juwap beriw kerek.

H=30*2+25=70sm

Fundamentin' biyikligin 70sm etip qabillaymiz ha'm h <1 bolg'ani ushin 2 teksheli etip alamiz h1=30sm, h2=40sm.

h0=70sm - 3sm=67sm

h01=30sm - 3sm=27sm

a1=30sm + 2*40sm=110sm

To'mengi tekshenin' qiya ku'shke biyikligin aniqlaymiz.

l=(- - ^ - ho)

2 2 01

,2.1m 0.3m .

l=(— 0. 6 7m)=0.23m

6rp*l < 1.5*Rbt*h01 78.2kN/m < 409.5kN/m l-l ha'm ll-ll tekshelerdegi iyiwshi ku'sh momenti to'mendegishe aniqlandi;

Mi=0.125*Rrp*(a-hk)2*b M1=0.125*340kN/m2*(2.1m-0.3m)2*2.1m=289kN*m

M2=0.125*Rrp*(a-a1)2*b M2=0125*340kN/m2*(2.1m-1.1m)2*2.1m=89kN*m Almatura kesim maydanin aniqlaymiz;

Mi
A S ! = b


r*ho*Rs

16

Ш

2890000 kg*sm ^


As-1 = -=17.75sm

0.9*67m*3400 kg/sm2



M1
A 5 2 = 1


r*hoi*Rs

890000kg*sm „ _ __ ,


As2 = ; r=13.56sm

0.9*27m*3400 kg/sm2


l-l boyinsha boyinsha 12 014 £A s =18.47sm2

18.47sm2


ц= *100 %=0.1%.

210sm*67sm

17

2

4


2


3




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