Educational, natural and social sciences

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46 Ahmadqul Tilagov 359-364

Oriental Renaissance: Innovative, educational, natural and social sciences VOLUME 2 | ISSUE 2 ISSN 2181-1784
Javob:1 4-Masala.

Javob:

2-Masala.
tekislikning tashqarisidagi S nuqtadan unga uchta teng SA, SB, SC og’ma va
SO perpendikuliyar o’tkazilgan. Perpendikuliyarning O asosi ABC uchburchakka
tashqi chizilgan aylananing markazi bo’lishini isbotlang.
Isbot: Berilgan nuqtadan uchburchak tekisligiga perpendikulyar tushirsak,
quyidagi uchburchaklar hosil bo’ladi
Bu uchburchaklar GK
alomatiga ko’ra o’zaro teng. Demak uchburchak
Chunki masala shartiga ko’ra SA= SB= SC og’malar teng,
hamda SO perpendikulyar umumiy.
Bundan, AO=BO=CO tenglik hosil bo’ladi.
Bu tomonlar tengligidan,
uchburchak
ichidagi ixtiyoriy O nuqtadan uchburchak uchlarigacha
A
a
a
a
a
a
a
S
a
a
A
C
B
o
R

Oriental Renaissance: Innovative,
educational, natural and social sciences

VOLUME 2 | ISSUE 2
ISSN 2181-1784
Scientific Journal Impact Factor

SJIF 2022: 5.947
Advanced Sciences Index Factor
ASI Factor = 1.7
363
w
www.oriens.uz
February
2022

bo’lgan masofalar teng . Faqat uchburchakka tashqi chizilgan aylanadagina
uchburchakning uchlaridan aylana markazigacha bo’lgan masofalar teng bo’ladi.
Bundan O nuqta uchburchakka tashqi chizilgan aylana markazi ekani kelib chiqadi.
3-Masala.
Teng tomonli uchburchakning tomonlari 3m ga teng. Uchburchak har biri
uchidan 2m masofada bo’lgan nuqtadan uchburburchak tekisligigacha bo’lgan
masofani toping.
2)
=1
Javob:1

4-Masala.
A nuqtadan kvadratning uchlarigacha bo’lgan masofa a ga teng. Kvadratning
tomoni b ga teng bo’lsa, A nuqtadan kvadrat tekisligigacha bo’lgan masofani toping.
1)
2)
3)
4)

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