• 2.1.6-masala.
  • Buxoro davlat universiteti




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    2.1.5-masala.Ikki shahardan bir-biriga qarama-qarshi ikki turist yo`lga chiqdi.Birinchisi avtomabilda tezligi 62 km/soat,ikkinchisi avtobusda tezligi48 km/soat.Agar ular 0,6 soatdan keyin uchrashgan bo`lsa,shaharlar orasidagi masofani toping?

    A)70km B)62 km C)64 km D)66km



    Yechish:Yuqoridagi formuladan foydalansak,uchrashish vaqti t=0,6 soat, V1=62 km/soat,V2=48 km/soat ga teng.

    S=t(V1+V2) , S=0,6(62+48)=0,6*110=66 km

    Javob:D ekan.

    2.1.6-masala.Yo`lovchilar poyezdining 3 soatda yurgan masofasiyuk poyezdining 4 soatda yurgan masofasidan 10 km ortiq.Yuk poyezining tezligi yo`lovchilar poyezdining tezligidan 20 km/soatga kam.Yuk poyezddining tezligini toping.

    A)40 B)45 C)48 D)50



    Yechish:Abiturentlar masalaning shartiga e`tiborni qaratib,unga mos tenglama tuzib olishlari kerak bo`ladi.Yo`lovchi poyezdi S1=3V1 masofani bosib o`tsin, yuk poyezdi S2=4V2bosib o`tadi. Bosib o`tgan yo`llar farqi 10 km ga teng.V1=V2+20

    3V1=4V2+10 tenglamaga V1=V2+20 ni qo`ysak. 3V2+60=4V2+10, V2=50 km/soat

    Javob: 50km/soat D.



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