54
Misollar
1.
(
√
)
Nyuton binomi formulasidan foydalanib yoying.
J:
√
√
√
2.
yoyilmasidan eng katta koeffitsiyentni toping.
J: 5!
3.
(
√
)
binom yoyilmasining o„rta hadini toping.
J:
(
√
)
(
√
)
4.
(
√ )
binom yoyilmasining
qatnashgan hadinining
nomerini toping.
J: 5.
5.
(√
√
√
√
)
binom yoyilmasida
va
qiymatning bir xil
darajalari qatnashgan hadining nomerini toping.
J: Bunday had mavjud emas.
6.
(
)
binom formulasidan foydalanib yoying.
J:
(
)
(
)
(√ )
√
(√ )
( √
)
( √
)
√
7.
(
√
√
√
√ ( √
√
)
√ )
ifoda soddalashtirilsin va yoyilmaning
qatnashmagan hadi topilsin.
J:
beshinchi had,
√
8. Bir binomning daraja ko„rsatkichi ikkinchi binomning daraja
ko„rsatkichidan 6 ta kam, har ikkala yoyilma binom koeffitsiyentlarining
yig„indisini o„nli logarifmlarini qo„shsak, natija 0 ga teng. Shu
ko„rsatkichni toping.
J:
9.
(√
)
binom yoyilmasi uchinchi hadining koeffitsiyenti 36
soniga teng bo„lsa, shu yoyilmaning to„qqizinchi hadini toping.
J:
√
55
10.
(√
√
)
binom yoyilmasining oltinchi
hadi koeffitsiyenti uning
sakkizinchi hadi koeffitsiyentidan 21 marta katta. Yoyilmaning
qat-
nashmagan hadini toping.
